AP BIOLOGY

Detailed explanation-1: -If these three genes were independently assorting, then the triple heterozygote would make 8 gametes and have progeny showing 8 different phenotypes in equal frequencies.

Detailed explanation-2: -Map distance between 2 linked genes = number of recombinants (offspring with certain phenotypes) / total number of offspring (times) 100.

Detailed explanation-3: -In genetics, a three-point cross is used to determine the loci of three genes in an organism’s genome. An individual heterozygous for three mutations is crossed with a homozygous recessive individual, and the phenotypes of the progeny are scored.

Detailed explanation-4: -Map units can be determine by calculating the percent recombination (recombination frequency) between the two genes on the chromosome. One percent recombination is equal to one map unit, two percent recombination is equal to two map units, and so forth.