AP BIOLOGY

CELL DIVISION

CELL DIVISION AND CANCEROUS CELLS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
The diploid number of chromosomes of a dog is 28. During Meiosis I, one of the homologous chromosome pairs does not separate. How many chromosomes are there in any one of the gametes that would be produced?
A
13
B
14
C
27
D
28
Explanation: 

Detailed explanation-1: -A dog is a diploid organism and has 39 pairs of chromosomes (2n = 78), where n = 39 chromosomes from each parent.

Detailed explanation-2: -(See figure below, where meiosis I begins with a diploid (2n = 4) cell and ends with two haploid (n = 2) cells.) In humans (2n = 46), who have 23 pairs of chromosomes, the number of chromosomes is reduced by half at the end of meiosis I (n = 23).

Detailed explanation-3: -A meiocyte is diploid which undergoes meiosis to form haploid gametes. Gametes in turn fuse to form the diploid zygote. So the zygote of the dog will have the same number of the chromosomes as the meiocytes ie., 78.

Detailed explanation-4: -If a diploid cell containing 28 chromosomes undergoes meiosis, how many chromosomes will each daughter cell have? EXPLAIN. Each daughter cell will have 14 chromosomes. Meiosis results in haploid gametes, meaning each gamete will have half the original number of chromosomes as the diploid parent cell.

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