CELL DIVISION
MEIOSIS AND GENETIC VARIATION
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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0%
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25%
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50%
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75%
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Detailed explanation-1: -If both parents are carriers there is a 1 in 4 (25 percent) chance that both will pass on the non-functioning gene, which would result in a pregnancy affected with cystic fibrosis.
Detailed explanation-2: -When both parents are carriers (CN), every baby has 25% chance of having cystic fibrosis. If testing shows one parent is a carrier and the other parent is likely not a carrier, the chance of having a child with cystic fibrosis is significantly reduced.
Detailed explanation-3: -25 percent (1 in 4) the child will have CF. 50 percent (1 in 2) the child will be a carrier but will not have CF. 25 percent (1 in 4) the child will not be a carrier of the gene and will not have CF.
Detailed explanation-4: -Once parents have had a child with CF, they have a 1 in 4 chance that each additional child will be born with CF. This means there is a 3 out of 4 chance that additional children won’t have CF. But these children may be carriers of the CF gene. Most often a family has no history of CF.
Detailed explanation-5: -1-in-4 chance (25 percent) that your child will have CF.