CELL DIVISION
MEIOSIS AND GENETIC VARIATION
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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0%
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25%
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50%
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75%
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Detailed explanation-1: -If the father is heterozygous, there is a 50% probability for a blood type A child and a 50% probability for a blood type O child. If the father is homozygous, every offspring will be blood type A. The mother of the child is Rh+. She may be homozygous or she may be heterozygous with one Rh+ allele and one Rh-allele.
Detailed explanation-2: -In most cases, an O parent and an AB parent will have only A or B kids.
Detailed explanation-3: -Genotypes IA IA, IB IB, IO IO show A, B and O blood groups respectively. Due to codominance of “IA” and “IB” alleles, the genotype “IAIB” produce “AB” blood group respectively. Thus, the six genotypes give total four phenotypes. Hence, parents with A and B blood group can have child with A, B, AB and O blood groups.
Detailed explanation-4: -Finally, the parental genotypes in option (D), IAIB and IAIB, have a 50 percent chance of producing offspring with blood type AB, a 25 percent chance of producing offspring with blood type A, and a 25 percent chance of producing offspring with blood type B.