CELL DIVISION
MEIOSIS AND GENETIC VARIATION
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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1/16
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1/4
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1/2
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3/16
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Detailed explanation-1: -The predicted fraction is therefore 1/16.
Detailed explanation-2: -When crossing organisms that are heterozygous for two traits, the result is a dihybrid cross. The phenotypic ratio of a heterozygous dihybrid cross for autosomal (none-sex-linked) traits is always 9:3:3:1. Nine offspring will show both dominant traits (AABB, AaBB, AABb, AaBb).
Detailed explanation-3: -The scenario is outlined in the Punnett square below. There is only one possible offspring with the aabb phenotype of 16 total, so the fraction with this genotype will be 116 .
Detailed explanation-4: -A dihybrid cross has a 9:3:3:1 ratio. A dihybrid cross consist of two individuals who are heterozygous for two genes. AaBb x AaBb is the cross for this problem A dihybrid will express the dominant allele for both genes. The dihybrid parents have short grey fins.
Detailed explanation-5: -Total phenotpic combination= 16. Thus, the correct answer is option C. Was this answer helpful?