CELL DIVISION
MEIOSIS AND GENETIC VARIATION
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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What is the probability that the following parents:AABbcc x aabbCC will produce the following offspring:AaBbCc?
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0
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1/32
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1/16
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1/2
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1/4
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Explanation:
Detailed explanation-1: -The correct answer is the last choice, 1/64.
Detailed explanation-2: -Trihybrid Cross: Cross between two heterozygous individuals involving three different traits. A cross between AaBbCc and AaBbCc, which involves a cross of three different traits is an example of a trihybrid cross.
Detailed explanation-3: -In this way 8 types of phenotypes will be obtained from this cross-AaBbCc, AabbCc, AaBbcc, Aabbcc, aabbcc, aaBbcc, aabbCc and aaBbCc. Also, since in the heterozygous parent 3 genes are in heterozygous condition, i.e., n = 3, therefore according to the formula, 2n=23=8. Hence, 8 phenotypes are possible.
There is 1 question to complete.