AP BIOLOGY

CELL RESPIRATION

GLYCOLYSIS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
In the link reaction one molecule of pyruvate will produce ____ ?
A
pyruvate and carbon dioxide
B
carbon dioxide and co-enzyme A
C
carbon dioxide, acetyl coA and reduced NAD
D
Reduced NAD and carbon dioxide
Explanation: 

Detailed explanation-1: -During the link reaction, pyruvate is decarboxylated, meaning it loses carbon dioxide, so it becomes a two-carbon molecule. During this reaction, this two-carbon molecule is joined with another molecule called coenzyme A to make acetyl-CoA. Also during this reaction, a molecule of NAD+ is reduced to form NADH.

Detailed explanation-2: -During the link reaction, a carbon atom is removed from pyruvate, forming carbon dioxide. This converts pyruvate into a two-carbon molecule called acetate. Hydrogen is also removed from pyruvate in the conversion into acetate, which is picked up by the coenzyme NAD to form reduced NAD.

Detailed explanation-3: -Aerobic respiration takes place in the mitochondria and requires the presence of oxygen. Aerobic respiration begins with the conversion of pyruvate into acetyl CoA. This conversion begins with the decarboxylation (removal of CO2) of pyruvate.

Detailed explanation-4: -Two molecules of pyruvate are converted into two molecules of acetyl CoAstart text, C, o, A, end text. Two carbons are released as carbon dioxide-out of the six originally present in glucose.

Detailed explanation-5: -Firstly, the link reaction produces one molecule of carbon dioxide and one molecule of reduced NAD. Its final product, acetyl coenzyme A, becomes a primary reactant of the Krebs cycle. The Krebs cycle produces one molecule of FADH2 and three molecules of NADH.

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