CELL RESPIRATION
GLYCOLYSIS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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The cell will continue to produce energy from mitochondrial electron transport.
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The cell will continue to produce ATP using the citric acid cycle.
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The cell will ultimately be unable to produce ATP.
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The cell will be forced to switch to fermentation to produce ATP.
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Detailed explanation-1: -In the first step of glycolysis, the enzyme hexokinase uses ATP to transfer a phosphate to glucose to form glucose-6-phosphate. The product continues to be oxidized forming pyryvate in glycolysis and is a precursor to acetyl-CoA for the citric acid cycle.
Detailed explanation-2: -The first step in glycolysis is catalyzed by hexokinase, an enzyme with broad specificity that catalyzes the phosphorylation of six-carbon sugars. Hexokinase phosphorylates glucose using ATP as the source of the phosphate, producing glucose-6-phosphate, a more reactive form of glucose.
Detailed explanation-3: -The enzyme hexokinase phosphorylates or adds a phosphate group to glucose in a cell’s cytoplasm. In the process, a phosphate group from ATP is transferred to glucose producing glucose 6-phosphate or G6P. One molecule of ATP is consumed during this phase.
Detailed explanation-4: -Hexokinase occupies the key first step in erythrocyte glycolysis, converting glucose to glucose-6-phosphate with the expenditure of 1 mole of ATP. Deficiency of this enzyme was first noted by Lohr in patients with Fanconi’s panmyelopathy (298).