AP BIOLOGY

EVOLUTION

EVOLUTION OF A POPULATION

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A population is in Hardy-Weinberg equilibrium. The gene of interest has two alleles, with 16% of the population portraying the recessive phenotype. What is the frequency of the dominant allele?
A
84%
B
60%
C
48%
D
36%
Explanation: 

Detailed explanation-1: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.

Detailed explanation-2: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.

Detailed explanation-3: -If the homozygous recessive genotype makes of 16% of the population the fraction of the recessive allele is the square root of the q (recessive allele fraction )= √¯ 0.16 = 0.4. The dominant allele is 1-p = 1-0.4 = 0.6.

Detailed explanation-4: -In a certain population which is in Hardy Weinberg equilibrium, 36 % of individuals are homozygous for curly hair (CC). The gene for curly hair is dominant over the gene for straight hair, c.

There is 1 question to complete.