A population of 150 individuals has an allele frequency of 0.3 for the dominant allele (B). Use the Hardy-Weinberg equation to determine the frequency of the genotype (Bb).

EVOLUTION OF A POPULATION

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

A	0.09
B	0.42
C	0.49
D	0.21

Explanation:

Detailed explanation-1: -To determine q, which is the frequency of the recessive allele in the population, simply take the square root of q2 which works out to be 0.632 (i.e. 0.632 x 0.632 = 0.4). So, q = 0.63. Since p + q = 1, then p must be 1-0.63 = 0.37.

Detailed explanation-2: -In a population that is in Hardy-Weinberg equilibrium, 38 % of the individuals are recessive homozygotes for a certain trait.

Detailed explanation-3: -The Hardy-Weinberg equation is p2+2pq+q2=1 and is used to determine the frequency of genotypes in a given population. To solve for the frequency of a specific genotype, start by replacing the appropriate terms with the known values you’ve been given.

Detailed explanation-4: -To know if a population is in Hardy-Weinberg Equilibrium scientists have to observe at least two generations. If the allele frequencies are the same for both generations then the population is in Hardy-Weinberg Equilibrium.

There is 1 question to complete.