AP BIOLOGY

Detailed explanation-1: -Given that the 1% error from this is negligible, the population supports this and therefore the remaining 102 individuals, 51% of the population, would be heterozygotes expressing the dominant phenotype.

Detailed explanation-2: -Calculate the percentage of individuals homozygous for the dominant allele. We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09. Thus, p = 1 – q ∴ p = 1 – 0.30 = 0.70 ∴The homozygote dominants are represented by p2 = (0.70)2 = 0.49 or 49% Page 2 4.

Detailed explanation-3: -In a population of 200 mice, 98 are homozygous dominant for brown coat color (BB), 84 are heterozygous (Bb) and 18 are homozygous recessive (bb).

Detailed explanation-4: -Answer and Explanation: If 72 out of 200 individuals in the animal population are homozygous recessive, 48% of the population would be heterozygotes, and 16% would be homozygous dominant.

Detailed explanation-5: -In a population of 200 individuals, 72 are homozygous recessive for the character fragmented fins. One hundred individuals from this population die due to a fatal disease. Thirty six of the survivors are homozygous recessive.