AP BIOLOGY

EVOLUTION

EVOLUTION OF A POPULATION

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
If p = .63 and q = .37, which decimal would represent the likelihood that an organism would be heterozygous in a population in genetic equilibrium?
A
0.65
B
0.47
C
0.37
D
0.02
Explanation: 

Detailed explanation-1: -When a population is in Hardy-Weinberg equilibrium for a gene, it is not evolving, and allele frequencies will stay the same across generations. There are five basic Hardy-Weinberg assumptions: no mutation, random mating, no gene flow, infinite population size, and no selection.

Detailed explanation-2: -The Hardy-Weinberg equilibrium is a principle stating that the genetic variation in a population will remain constant from one generation to the next in the absence of disturbing factors.

Detailed explanation-3: -The conditions to maintain the Hardy-Weinberg equilibrium are: no mutation, no gene flow, large population size, random mating, and no natural selection.

Detailed explanation-4: -Which of the following statements best explains the need for the “2” in the 2pq term in the Hardy-Weinberg equation? Heterozygotes can come about in two ways. In a Hardy-Weinberg population with two alleles A1 and A2 that are in equilibrium, the frequency of the allele A2 is 0.3.

There is 1 question to complete.