EVOLUTION
EVOLUTION OF A POPULATION
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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.40
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.36
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.16
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.60
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Detailed explanation-1: -In a population that is in Hardy-Weinberg equilibrium, the frequency of homozygous dominant individuals is 0.36.
Detailed explanation-2: -Calculate the percentage of individuals homozygous for the dominant allele. We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09. Thus, p = 1 – q ∴ p = 1 – 0.30 = 0.70 ∴The homozygote dominants are represented by p2 = (0.70)2 = 0.49 or 49% Page 2 4.
Detailed explanation-3: -The frequency of heterozygous individuals. Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).
Detailed explanation-4: -The frequency of homozygous dominant plants (p2) is (0.6)2 = 0.36. Out of 100 individuals, there are 36 homozygous dominant (YY) plants. The frequency of heterozygous plants (2pq) is 2(0.6)(0.4) = 0.48. Therefore, 48 out of 100 plants are heterozygous yellow (Yy).