EVOLUTION
HARDY WEINBERG EQUILIBRIUM
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
|
0.09
|
|
|
0.42
|
|
|
0.49
|
|
|
0.21
|
Detailed explanation-1: -To determine q, which is the frequency of the recessive allele in the population, simply take the square root of q2 which works out to be 0.632 (i.e. 0.632 x 0.632 = 0.4). So, q = 0.63. Since p + q = 1, then p must be 1-0.63 = 0.37.
Detailed explanation-2: -The Hardy-Weinberg equation is p2+2pq+q2=1 and is used to determine the frequency of genotypes in a given population. To solve for the frequency of a specific genotype, start by replacing the appropriate terms with the known values you’ve been given.
Detailed explanation-3: -So, the correct answer is ‘0.64’
Detailed explanation-4: -For a three allele system: p, q and r, the frequencies can be denoted as: p2 + q2 + r2 + 2pq + 2pr + 2qr = 1. It is possible to display the data for a bi-allelic locus within a population graphically using a de Fitetti diagram. This graphical display is often referred to as the Hardy-Weinberg parabola.