AP BIOLOGY

EVOLUTION

HARDY WEINBERG EQUILIBRIUM

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
If 81% of the population is homozygous recessive for a given trait, what is the predicted frequency of homozygous dominant?
A
.81
B
.9
C
.1
D
none of the above
Explanation: 

Detailed explanation-1: -We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09.

Detailed explanation-2: -The frequency of homozygous dominant plants (p2) is (0.6)2 = 0.36. Out of 100 individuals, there are 36 homozygous dominant (YY) plants. The frequency of heterozygous plants (2pq) is 2(0.6)(0.4) = 0.48. Therefore, 48 out of 100 plants are heterozygous yellow (Yy).

Detailed explanation-3: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4. Since p+q = 1; thus the frequency of dominant allele = p = 1-q = 1-0.4 = 0.60.

Detailed explanation-4: -On sampling a population, the frequency of homozygous recessive genotype (aa) is 36%.

There is 1 question to complete.