EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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24
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72
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54
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150
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Detailed explanation-1: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.
Detailed explanation-2: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.
Detailed explanation-3: -An allele frequency is calculated by dividing the number of times the allele of interest is observed in a population by the total number of copies of all the alleles at that particular genetic locus in the population. Allele frequencies can be represented as a decimal, a percentage, or a fraction.
Detailed explanation-4: -The frequency of the B allele is 6/10 = 60%. A shortcut to counting the number of B alleles is to count how many BB genotypes there are, and multiply this by 2 (since each BB genotype has 2 B alleles), then add the number of Bb genotypes (since each Bb genotype has 1 B allele).