AP BIOLOGY

EVOLUTION

HARDY WEINBERG EQUILIBRIUM

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
In a population of cats, short hair is dominant to long hair. If 16% of a breeder’s cats have long hair, what is the frequency of the dominant allele?
A
0.16
B
0.6
C
0.4
D
0.36
E
.48
Explanation: 

Detailed explanation-1: -The “2pq” in equation shows frequency of heterozygotes in the population. In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.

Detailed explanation-2: -If the homozygous recessive genotype makes of 16% of the population the fraction of the recessive allele is the square root of the q (recessive allele fraction )= √¯ 0.16 = 0.4. The dominant allele is 1-p = 1-0.4 = 0.6.

Detailed explanation-3: -1 = p2 + 2pq + q2 P and q each represent the allele frequency of different alleles. The term p2 represents the frequency of the homozygous dominant genotype.

Detailed explanation-4: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.

There is 1 question to complete.