EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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p
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p2
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q
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q2
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2pq
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Detailed explanation-1: -In the question, the genotype frequency of recessive population is (q2) = (16% or 0.16). Hence, frequency of recessive allele = q = 0.16 = 0.4.
Detailed explanation-2: -Hardy-Weinberg Equations The second Hardy-Weinberg equation is used to determine genotype frequencies. The variable ‘p2’ denotes the homozygous dominant genotype (AA), ‘2pq’ denotes the heterozygous genotype (Aa), and ‘q2’ denotes the homozygous recessive genotype (aa).
Detailed explanation-3: -This is q2. Answer: Four of the sixteen individuals show the recessive phenotype, so the correct answer is 25% or 0.25.
Detailed explanation-4: -In a certain population which is in Hardy-Weinberg equilibrium, there are only two eye colours: brown (dominant) and blue (recessive). 16 % have blue eyes in the population.