# AP BIOLOGY

## EVOLUTION

### HARDY WEINBERG EQUILIBRIUM

 Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
In a population that is in Hardy-Weinberg equilibrium, the frequency of the homozygous recessive genotype is 0.25. What is the allele frequency of A or p?
 A 0.5 B 0.75 C 0.25 D 0.0625
Explanation:

Detailed explanation-1: -In a population that is in Hardy-Weinberg equilibrium, the frequency of the recessive homozygous genotype of a certain trait is 0.16.

Detailed explanation-2: -In a population that is in Hardy-Weinberg equilibrium, 38 % of the individuals are recessive homozygotes for a certain trait.

Detailed explanation-3: -The Hardy-Weinberg Equation q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p2 = the frequency of homozygous dominant genotype. q2 = the frequency of homozygous recessive genotype.

Detailed explanation-4: -Therefore, the frequency of the dominant phenotype equals the sum of the frequencies of AA and Aa, and the recessive phenotype is simply the frequency of aa. Therefore, the dominant frequency is 64% and, in the first part of this question above, you have already shown that the recessive frequency is 36%.

There is 1 question to complete.