EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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In a population that is in Hardy-Weinberg equilibrium, the frequency of the homozygous recessive genotype is 0.25. What is the frequency of being heterozygous dominant?
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0.5
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0.75
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.25
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0.0625
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Explanation:
Detailed explanation-1: -In a population that is in Hardy-Weinberg equilibrium, the frequency of the recessive homozygous genotype of a certain trait is 0.16.
Detailed explanation-2: -We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09.
Detailed explanation-3: -So, the correct answer is ‘0.64’
Detailed explanation-4: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype.
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