# AP BIOLOGY

## EVOLUTION

### HARDY WEINBERG EQUILIBRIUM

 Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
In the Hardy-Weinberg Equation, q2 is the frequency of what if you used the alleles A and a?
 A The recessive allele or a B the dominant allele or A C the recessive genotype or aa D the dominant genotype of AA E the dominant genotype of Aa
Explanation:

Detailed explanation-1: -q2 = percentage of homozygous recessive individuals. 2pq = percentage of heterozygous individuals.

Detailed explanation-2: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.

Detailed explanation-3: -We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09.

Detailed explanation-4: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p2 = the frequency of homozygous dominant genotype.

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