EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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frequency of The recessive allele
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frequency of the dominant allele
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frequency of the recessive genotype
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frequency of homozygous recessive individuals
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Detailed explanation-1: -The frequency of the recessive allele. Answer: Since we believe that the homozygous recessive for this gene (q2) represents 4% (i.e. = 0.04), the square root (q) is 0.2 (20%). The frequency of the dominant allele.
Detailed explanation-2: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
Detailed explanation-3: -We know that the frequency of the recessive homozygote genotype is q2 and equal to 0.09.
Detailed explanation-4: -Hardy Weinberg equation says, p2+2pq+q2=1, where q2 is the frequency of homozygous recessive gene.
Detailed explanation-5: -In a population that is in Hardy-Weinberg equilibrium, the frequency of the recessive homozygous genotype of a certain trait is 0.16.