EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A = 0.42, a = 0.12
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A = 0.6, a = 0.4
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A = 0.65, a = 0.35
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A = 0.84, a = 0.24
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Detailed explanation-1: -The frequency of genotype AA is determined by squaring the allele frequency A. The frequency of genotype Aa is determined by multiplying 2 times the frequency of A times the frequency of a. The frequency of aa is determined by squaring a. Try changing p and q to other values, ensuring only that p and q always equal 1.
Detailed explanation-2: -The frequency of the “aa” genotype. Answer: 36%, as given in the problem itself. The frequency of the “a” allele. Answer: The frequency of aa is 36%, which means that q2 = 0.36, by definition.
Detailed explanation-3: -To find the allele frequencies, we again look at each individual’s genotype, count the number of copies of each allele, and divide by the total number of gene copies.
Detailed explanation-4: -An allele frequency is calculated by dividing the number of times the allele of interest is observed in a population by the total number of copies of all the alleles at that particular genetic locus in the population. Allele frequencies can be represented as a decimal, a percentage, or a fraction.