AP BIOLOGY

EVOLUTION

HARDY WEINBERG EQUILIBRIUM

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What part of the Hardy Weinberg formula is used to determine the allele frequency of heterozygous genotypes (Aa)?
A
p2
B
2pq
C
q2
Explanation: 

Detailed explanation-1: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.

Detailed explanation-2: -Answer and Explanation: In the Hardy-Weinberg Theorem it states p2 +2pq + q2 = 1. p2 represents the frequency of the homozygous dominant genotype, q2 represents the frequency of the homozygous recessive genotype, and 2pq represents the frequency of the heterozygous genotype.

Detailed explanation-3: -p = frequency of the dominant allele in the population. q = frequency of the recessive allele in the population. p2 = percentage of homozygous dominant individuals. q2 = percentage of homozygous recessive individuals. 2pq = percentage of heterozygous individuals.

Detailed explanation-4: -The frequency of genotypes in a population may be calculated using the formula p2 + q2 + 2pq = 1, where p2 represents the frequency of homozygous dominant genotype, q2 represents the frequency of recessive genotype, and 2pq represents the frequency of heterozygous genotype.

Detailed explanation-5: -Explanation: In the Hardy-Weinberg equilibrium equation ( p2+2pq+q2=1 ), the term 2pq represents the genotype frequency of heterozygotes (Aa) in a population in equilibrium. The term p2 represents the frequency of dominant homozygotes (AA) and the term q2 represents the frequency of recessive homozygotes (aa).

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