# AP BIOLOGY

## EVOLUTION

### HARDY WEINBERG EQUILIBRIUM

 Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
What part of the Hardy Weinberg formula is used to determine the allele frequency of homozygous recessive genotypes (aa)?
 A p2 B 2pq C q2
Explanation:

Detailed explanation-1: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype. p2 = the frequency of homozygous dominant genotype.

Detailed explanation-2: -Hardy Weinberg equation says, p2+2pq+q2=1, where q2 is the frequency of homozygous recessive gene.

Detailed explanation-3: -Hardy-Weinberg Equations The second Hardy-Weinberg equation is used to determine genotype frequencies. The variable ‘p2’ denotes the homozygous dominant genotype (AA), ‘2pq’ denotes the heterozygous genotype (Aa), and ‘q2’ denotes the homozygous recessive genotype (aa).

Detailed explanation-4: -The frequency of the “aa” genotype. Answer: 36%, as given in the problem itself. The frequency of the “a” allele. Answer: The frequency of aa is 36%, which means that q2 = 0.36, by definition.

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