EVOLUTION
HARDY WEINBERG EQUILIBRIUM
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
p + q = 1
|
|
p2 + 2pq + q2 = 1
|
|
p2 + pq2 + q2 = 1
|
|
p + 2pq + q3 = 1
|
Detailed explanation-1: -The frequency of alleles in a population can be represented by p + q = 1, with p equal to the frequency of the dominant allele and q equal to the frequency of the recessive allele.
Detailed explanation-2: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.
Detailed explanation-3: -The Hardy-Weinberg Equation p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype.
Detailed explanation-4: -p = frequency of the dominant allele in the population. q = frequency of the recessive allele in the population. p2 = percentage of homozygous dominant individuals. q2 = percentage of homozygous recessive individuals. 2pq = percentage of heterozygous individuals.
Detailed explanation-5: -Hardy-Weinberg Equations The second Hardy-Weinberg equation is used to determine genotype frequencies. The variable ‘p2’ denotes the homozygous dominant genotype (AA), ‘2pq’ denotes the heterozygous genotype (Aa), and ‘q2’ denotes the homozygous recessive genotype (aa).