# AP BIOLOGY

## EVOLUTION

### HARDY WEINBERG EQUILIBRIUM

 Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Which Hardy-Weinberg equation represents the dominant and recessive allele frequencies in a population?
 A p + q = 1 B p2 + 2pq + q2 = 1 C p2 + pq2 + q2 = 1 D p + 2pq + q3 = 1
Explanation:

Detailed explanation-1: -The frequency of genotypes in a population can be represented by p2+2pq+q2= 1, with p2 equal to the frequency of the homozygous dominant genotype, 2pq equal to the frequency of the heterozygous genotype, and q2 equal to the frequency of the recessive genotype.

Detailed explanation-2: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so p + q = 1.

Detailed explanation-3: -The Hardy-Weinberg Equation The terms of this equation are defined as follows: p = the frequency of the dominant allele in a population. q = the frequency of the recessive allele in a population. 2 p q 2pq 2pq = the frequency of the heterozygous dominant genotype.

Detailed explanation-4: -In the Hardy-Weinberg Theorem it states p2 +2pq + q2 = 1. p2 represents the frequency of the homozygous dominant genotype, q2 represents the frequency of the homozygous recessive genotype, and 2pq represents the frequency of the heterozygous genotype.

Detailed explanation-5: -For values of p from 0 to 1, in intervals of 0.1, here’s what we get: p+q=1, so p=1-q and q=1-p. Red represents the frequency of the AA or A1A1 genotype, green is the Aa or A1A2 genotype, and blue is the aa or A2A2 genotype. All of the above has to do with the allele and genotype frequencies we would expect to see.

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