EVOLUTION
HARDY WEINBERG EQUILIBRIUM
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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p + q = 1
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p2 + 2pq + q2 = 1
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p2 + pq2 + q2 = 1
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p + 2pq + q3 = 1
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Detailed explanation-1: -Hardy-Weinberg equation is p2 + 2pq + q2 = 1. Here p is the frequency of the “A” allele and q is the frequency of the “a” allele in the population.
Detailed explanation-2: -Answer and Explanation: In the Hardy-Weinberg Theorem it states p2 +2pq + q2 = 1. p2 represents the frequency of the homozygous dominant genotype, q2 represents the frequency of the homozygous recessive genotype, and 2pq represents the frequency of the heterozygous genotype.
Detailed explanation-3: -The frequency of genotypes in a population may be calculated using the formula p2 + q2 + 2pq = 1, where p2 represents the frequency of homozygous dominant genotype, q2 represents the frequency of recessive genotype, and 2pq represents the frequency of heterozygous genotype.
Detailed explanation-4: -The Hardy-Weinberg genotype frequencies, p2 + 2pq + q2, represent the binomial expansion of (p + q)2, and also sum to one (as must the frequencies of all genotypes in any population, whether it is in Hardy-Weinberg equilibrium).