EVOLUTION
HISTORICAL CONTEXT FOR EVOLUTIONARY THEORY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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p + q = 1
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p2 + 2pq + q2 = 1
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p2 + pq2 + q2 = 1
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p + 2pq + q3 = 1
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Detailed explanation-1: -Hardy-Weinberg equation is p2 + 2pq + q2 = 1. Here p is the frequency of the “A” allele and q is the frequency of the “a” allele in the population.
Detailed explanation-2: -The Hardy-Weinberg genotype frequencies, p2 + 2pq + q2, represent the binomial expansion of (p + q)2, and also sum to one (as must the frequencies of all genotypes in any population, whether it is in Hardy-Weinberg equilibrium).
Detailed explanation-3: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.
Detailed explanation-4: -In the Hardy-Weinberg Theorem it states p2 +2pq + q2 = 1. p2 represents the frequency of the homozygous dominant genotype, q2 represents the frequency of the homozygous recessive genotype, and 2pq represents the frequency of the heterozygous genotype.
Detailed explanation-5: -The Hardy-Weinberg equation used to determine genotype frequencies is: p2 + 2pq + q2 = 1. Where ‘p2’ represents the frequency of the homozygous dominant genotype (AA), ‘2pq’ the frequency of the heterozygous genotype (Aa) and ‘q2’ the frequency of the homozygous recessive genotype (aa).