AP BIOLOGY

EVOLUTION

HISTORICAL CONTEXT FOR EVOLUTIONARY THEORY

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Which Hardy-Weinberg factor represents the frequency of heterozygous individuals in a population?
A
p2
B
2pq
C
q2
D
p2 + 2pq
Explanation: 

Detailed explanation-1: -In the equation, p2 represents the frequency of the homozygous genotype AA, q2 represents the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.

Detailed explanation-2: -Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).

Detailed explanation-3: -Answer and Explanation: In the Hardy-Weinberg Theorem it states p2 +2pq + q2 = 1. p2 represents the frequency of the homozygous dominant genotype, q2 represents the frequency of the homozygous recessive genotype, and 2pq represents the frequency of the heterozygous genotype.

Detailed explanation-4: -Finally according to Hardy Weinberg Equilibrium, the frequency of the heterozygous genotype (a carrier in this case ) is 2pq. This carrier frequency is 2 x 1/50 x 1 = 1/25.

Detailed explanation-5: -So, the correct answer is ‘2pq’

There is 1 question to complete.