HEREDITY
CODOMINANCE
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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0%
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25%
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50%
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75%
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Detailed explanation-1: -Homozygous dominant: 25% or 0.25. Heterozygous: 50% or 0.50. 11. If two heterozygotes are crossed, the probability that an offspring will show the dominant trait is 75% or 0.75.
Detailed explanation-2: -The chance of either parent being a heterozygote is 1/4, as calculated above. Then, the probability that both parents are heterozygotes, and the probability that two heterozygotes will have a heterozygous child, is 1/4 x 1/4 x 1/2 = 1/32.
Detailed explanation-3: -We know that when two people who are both heterozygous for a simple Mendelian autosomal gene alpha have a child, the probability that the child will show the dominant phenotype is 3/4.
Detailed explanation-4: -In another example (shown below), if the parent plants both have heterozygous (YG) genotypes, there will be 25% YY, 50% YG, and 25% GG offspring on average. These percentages are determined based on the fact that each of the 4 offspring boxes in a Punnett square is 25% (1 out of 4).