HEREDITY
INCOMPLETE DOMINANCE
|
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
|
|
|
100 %
|
|
|
75%
|
|
|
50%
|
|
|
25%
|
Detailed explanation-1: -Answer and Explanation: A heterozygous individual has two different alleles for a particular gene. In this case, the individual would have a 50% chance of inheriting one allele and a 50% chance of inheriting the other allele. The probability of getting heterozygous offspring for both genes is 1/4.
Detailed explanation-2: -If the father is heterozygous, there is a 50% probability for a blood type A child and a 50% probability for a blood type O child. If the father is homozygous, every offspring will be blood type A. The mother of the child is Rh+. She may be homozygous or she may be heterozygous with one Rh+ allele and one Rh-allele.
Detailed explanation-3: -One combination, OO, gives blood type O. So there’s a 1 out of 4, or 25% chance, that the child will have blood type O and 3 out of 4, or 75% chance that the child will have blood type A.
Detailed explanation-4: -The father should have a genotype of AO, and the mother should have a genotype of BO. Based on Punnett Square, there is a 25% probability that the child will have an O-blood type. There is also a 25% probability that the offspring will either have an AB, A, or B blood type.