HEREDITY
LAW OF DOMINANCE
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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1RR:2Rr:1rr
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2RR:2Rr:0rr
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0RR:4Rr:0rr
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0RR:0Rr:4rr
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Detailed explanation-1: -A pure round seed plant is crossed with the pure wrinkled seed plant. The genotypic ratio shall be 1:2:1. Q. In garden pea plant, a pure line with round seeds(RR) is crossed with a pure line having wrinkled seeds (rr).
Detailed explanation-2: -In the F1 generation, 50% of the offspring produced wrinkled seeds.
Detailed explanation-3: -The selfing of F1 will give F2 generation, where there will be one homozygous dominant round seed plant (RR), two heterozygous round seed plants (Rr) and 1 homozygous recessive wrinkled seed plant (rr). Phenotypically, there will be 3 round seed plants and 1 wrinkled seed plant. Hence, the correct answer is ‘3:1’.
Detailed explanation-4: -A round seeded plant ( R ) is dominant to a wrinkled seeded plant ( r). What parental genotypes will produce offspring that are 50% homozygous dominant and 50% heterozygous dominant ? Q. Round seeded (RR) plant is crossed with wrinkled seeded plant (rr).
Detailed explanation-5: -Final answer: If a round, green seeded pea plant (RRyy) is crossed with a wrinkled, yellow seeded pea plant, (rrYY) the seeds produced in the F1 generation are round and yellow.