AP BIOLOGY

HEREDITY

LAW OF DOMINANCE

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
Tay-Sachs disease is a lethal, autosomal recessive genetic disorder. If both parents are heterozygous carriers of the disease, what are the chances of them having a child who is also a heterozygous carrier for Tay-Sachs?
A
25%
B
50%
C
75%
D
100%
Explanation: 

Detailed explanation-1: -If you are born to parents who both carry the same autosomal recessive gene, you have a 25% (1 in 4) chance of inheriting the abnormal gene from both parents and developing the disease. You have a 50% (1 in 2) chance of inheriting one abnormal gene.

Detailed explanation-2: -The risk for two carrier parents to both pass the altered gene and have an affected child is 25% with each pregnancy. The risk to have a child who is a carrier like the parents is 50% with each pregnancy. The chance for a child to receive the normal genes from each parent is 25%.

Detailed explanation-3: -When both parents carry the defective Tay-Sachs gene, a child has a 25% chance of developing the disease. The child must receive two copies of the defective gene, one from each parent, in order to become sick. If only one parent passes the defective gene to the child, the child is called a carrier.

Detailed explanation-4: -If 2 people who are carriers have a child, there’s a: 1 in 4 (25%) chance the child won’t inherit any faulty genes and won’t have Tay-Sachs disease or be able to pass it on. 1 in 2 (50%) chance the child inherits a faulty gene from one parent and becomes a carrier, but won’t have the condition themselves.

Detailed explanation-5: -Carriers of an autosomal recessive disease usually do not have any symptoms of the disease. When two carriers of an autosomal recessive disease have children, there is a 25% (1 in 4) chance to have a child who has the disease.

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