AP BIOLOGY

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HEREDITY

LINKED GENES

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
If the distance between A/B is 0.12 mu and gene C is on the opposite side of A with respect to B at a distance of 0.23 mu, Which is the central gene in this map
A
B
B
A
C
C
D
Data insufficient
Explanation: 

Detailed explanation-1: -∙ The more the distance between the gene on chromosomes, then gene shows weak linkage and follow crossing over to form new combination of genetic material and the less the distance between the genes the greater the linkage.

Detailed explanation-2: -As shown in the next video, the map distance between loci B and E is determined by the number of recombinant offspring. Remember: The # of recombinant offspring / total # of offspring x 100% = recombination frequency. Recombination frequency = map units = centiMorgan (cM)

Detailed explanation-3: -Map distance between 2 linked genes = number of recombinants (offspring with certain phenotypes) / total number of offspring (times) 100.

Detailed explanation-4: -Genes independently assort at a distance of 50 cM or more apart.

There is 1 question to complete.
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