HEREDITY
LINKED GENES
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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A, B, C
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A, C, B
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B, C, A
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B, A, C
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Detailed explanation-1: -The map distances between genes A and B is 3 units, between B anc C is 10 units and between C and A is 7 units. The order of the genes in a linkage map constructed on the above data would perhaps be: Q.
Detailed explanation-2: -As shown in the next video, the map distance between loci B and E is determined by the number of recombinant offspring. Remember: The # of recombinant offspring / total # of offspring x 100% = recombination frequency. Recombination frequency = map units = centiMorgan (cM)
Detailed explanation-3: -Gene map distance is the distance between points on a chromosome which can be estimated by counting the number of crossovers between them. Therefore, the distance between two points on the genetic map of a chromosome is the average number of crossovers between them.
Detailed explanation-4: -Summary. To calculate distance on a map you must do the following: Measure distance between two points on a map in cm or mm. Multiply this by the scale of the map and divide by 100 000 if you used centimetres or by 1000 000 if you used millimetres to get kilometres.