What is the map distance if the following offspring are produced:345 wild, 8 wild/yellow, 10 vestigial/wild, 325 yellow/vestigial? (note:these are not given as percents!)

LINKED GENES

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

A	97.3
B	2.6
C	18
D	1.8

Explanation:

Detailed explanation-1: -Remember: The # of recombinant offspring / total # of offspring x 100% = recombination frequency. Recombination frequency = map units = centiMorgan (cM)

Detailed explanation-2: -The linkage distance is calculated by dividing the total number of recombinant gametes into the total number of gametes.

Detailed explanation-3: -The distance between the genes can be written as a percentage or as a MAP UNIT. The gene for body color and and wing size are 17 map units apart.

Detailed explanation-4: -Gene map distance is the distance between points on a chromosome which can be estimated by counting the number of crossovers between them. Therefore, the distance between two points on the genetic map of a chromosome is the average number of crossovers between them.

There is 1 question to complete.

AP BIOLOGY

HEREDITY

LINKED GENES