# AP BIOLOGY

## HEREDITY

### MONOHYBRID CROSS

 Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A homozygous dominant mom mated with a father that is homozygous recessive. Create a Punnett square to determine how many of the offspring will have freckles
 A 0 B 4 C 3 D 1
Explanation:

Detailed explanation-1: -For example, if one parent is homozygous dominant (WW) and the other is homozygous recessive (ww), then all their offspring will be heterozygous (Ww) and possess a widow’s peak.

Detailed explanation-2: -Since we already know which genotypes will produce offspring with freckles, we can see that three of the four potential offspring have a genotype that would produce freckles. So there’s a 75 percent probability that a couple who are both heterozygous for the allele for freckles will have a child who has freckles.

Detailed explanation-3: -The first is homozygous, which means two copies of the same allele, like BB for two dominant alleles or bb for two recessive alleles. The other possible combination is heterozygous, which means one of each type of allele, like Bb for one dominant and one recessive allele.

Detailed explanation-4: -A single trait Punnett Square tracks two alleles for each parent. The square has two rows and two columns. Adding more traits increases the size of the Punnett Square.

There is 1 question to complete.