AP BIOLOGY

HEREDITY

MONOHYBRID CROSS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A round seed plant (R) is dominant to a wrinkled seed plant (r). A homozygous round seeded plant is crossed with a homozygous wrinkled seeded plant. What percentage of offspring will also be homozygous?
A
0% will be homozygous
B
25% will be homozygous
C
50% will be homozygous
D
1000% will be homozygous
Explanation: 

Detailed explanation-1: -Thus 50% of the offsprings will be homozygous round seeded whereas 50% will be heterozygous round seeded plants.

Detailed explanation-2: -In the F1 generation, 50% of the offspring produced wrinkled seeds.

Detailed explanation-3: -Since capital R = round and is dominant that means that RR and Rr will all be round seeds. That means that ¾ or 75% of the offspring produced will be round. Since, wrinkled is rr, then ¼ or 25% of the offspring will be wrinkled. The genotype is the gene make-up of the offspring.

Detailed explanation-4: -A cross between homozygous round seeds plant (RR) and homozygous wrinkled seeds plant (rr) will produce heterozygous (Rr) round seeds plants as F1 generation.

Detailed explanation-5: -In pea plant, round seed is a dominant trait while wrinkled seed is a recessive trait. Here, ‘R’ is the dominant allele and ‘r’ is the recessive allele for the seed shape of the pea plant. The plant with round seeds would have genotype RR. Then, the plant with genotype rr would have wrinkled seeds.

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