HEREDITY
MONOHYBRID CROSS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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If a heterozygous mother with brown eyes mated with a father who is homozygous dominant for brown eyes. Create a Punnett square to determine the percentage of offspring would have brown eyes?
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100%
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75%
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50%
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25%
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Explanation:
Detailed explanation-1: -Homozygous dominant: 25% or 0.25. Heterozygous: 50% or 0.50. 11. If two heterozygotes are crossed, the probability that an offspring will show the dominant trait is 75% or 0.75.
Detailed explanation-2: -What are the resulting percentages of genotypes of a cross between a homozygous dominant parent and a heterozygous parent? Explanation: The answer is 50% BB and 50% Bb, as shown in the punnet square below.
Detailed explanation-3: -For two parents with brown eyes to have a blue-eyed child, both parents must genetically be Bb. When this happens, there is a 1 in 4 chance that these parents will have a bb child with blue eyes.
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