AP BIOLOGY

HEREDITY

MONOHYBRID CROSS

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Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]

If a heterozygous mother with brown eyes mated with a father who is homozygous dominant for brown eyes. Create a Punnett square to determine the possible genotypes of the offspring?

A	homozygous dominant & heterozygous
B	homozygous dominant only
C	heterozygous and homozygous recessive
D	heterozygous only

Explanation:

Detailed explanation-1: -Because homozygous dominant and heterozygous individuals are phenotypically identical, the observed traits in the F2 offspring will exhibit a ratio of three dominant to one recessive.

Detailed explanation-2: -Homozygous dominant: 25% or 0.25. Heterozygous: 50% or 0.50. 11. If two heterozygotes are crossed, the probability that an offspring will show the dominant trait is 75% or 0.75.

Detailed explanation-3: -The heterozygous parent must have two different genes, and at least one for the dominant brown eyes (B). These parents must have the genotypes of (bb) and (Bb). There is a 50% chance of an offspring having a (Bb) genotype, and thus brown eyes.

Detailed explanation-4: -For two heterozygote parents (Aa), 1/4 of all offspring would be expected to show the recessive trait of albinism.

There is 1 question to complete.