HEREDITY
MONOHYBRID CROSS
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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SS x SS
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SS x ss
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ss x ss
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SS x Ss
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Detailed explanation-1: -Short hair is dominant which means it can express in both heterozygous(Hh) and homozygous condition(HH). If all the progeny have short hair, then the parents should have been either: HH x HH OR HH x Hh OR HH x hh.
Detailed explanation-2: -In guinea pigs, short hair (S) is dominant over long hair (s). A female guinea pig with short hair but whose father had long hair is mated with a male with long hair but whose parents were both shorthaired. Using a Punnett square, predict the genotypic and phenotypic ratios of their offspring.
Detailed explanation-3: -So, Bb X Bb gives genotypes BB, Bb and bb which are the possible genotypes for guinea pig.
Detailed explanation-4: -The dominant allele for short hair is represented by capital A and the recessive allele for long hair is represented by letter a. If two heterozygous parents (Aa) are crossed, the possible genotypes of offspring are AA, Aa, Aa, and aa.
Detailed explanation-5: -In guinea pigs, the allele for short hair is dominant.