HEREDITY
MONOHYBRID CROSS
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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Ss + Ss
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SS + SS
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SS + Ss
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ss + ss
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SS + ss
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Detailed explanation-1: -Short hair is dominant which means it can express in both heterozygous(Hh) and homozygous condition(HH). If all the progeny have short hair, then the parents should have been either: HH x HH OR HH x Hh OR HH x hh.
Detailed explanation-2: -In guinea pigs, short hair (S) is dominant over long hair (s). A female guinea pig with short hair but whose father had long hair is mated with a male with long hair but whose parents were both shorthaired. Using a Punnett square, predict the genotypic and phenotypic ratios of their offspring.
Detailed explanation-3: -The genotypes of 2 guinea pigs, for 2 traits are represented as AABB and aabb. The guinea pigs are mated and the offspring eventually mate with eachother.
Detailed explanation-4: -In Guinea pigs, the genotype (BB) is black, and the genotype (bb) is white color, and (Bb) is grey color, The gene (B) and (b) are sex-linked.
Detailed explanation-5: -There is a 50-75% or about half chance that the babies bred by a Skinny Pig and a haired Skinny pig gene carrier, will have hairless Skinny pig babies. The rest of the babies will just be skinny pig gene carriers. There is only a 25% chance that 1 or so hairless skinny babies will be born in these litters.