AP BIOLOGY

Detailed explanation-1: -Answer: Genotype of a plant pea heterozygous for round seeds and homozygous recessive for green seeds is (d) Rryy. Starting genotype of parents in a dihybrid cross would be (d) RrYy and RrYy.

Detailed explanation-2: -Complete answer: The genotype of yellow round seeds is YYRR and the genotype of green wrinkled seeds is yyrr. In the $F 1$ generation, the progenies obtained are heterozygous yellow round since yellow and round are dominant characters.

Detailed explanation-3: -Hence the genotype of the heterozygous yellow seeded plant will be “Yy” and that for green seeded plant will be “yy” (as the recessive allele is expressed only in homozygous conditions).

Detailed explanation-4: -What will be the phenotype of the offspring when a pea plant homozygous for round seeds is crossed with a pea plant producing wrinkled seeds? Q. A pea plant producing round seeds is crossed with another pea plant producing wrinkled seeds. In the F1 generation, 50% of the offspring produced wrinkled seeds.

Detailed explanation-5: -A pea plant with round seeds has the genotype Rr. You can cross this plant with wrinkled seed plant, genotype rr.