AP BIOLOGY

HEREDITY

MULTIPLE ALLELES

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
A type B man (genotype BO) marries a woman with type A (AA) . What percent chance will they have of making a type AB offspring?
A
0%
B
25%
C
50%
D
100%
Explanation: 

Detailed explanation-1: -Since the mother has A blood group, the child can not be homozygous for B blood group. The reason is that he will receive one IB allele from father with B blood group but the mother with A blood group can transmit only IO allele for the child to have B blood group. Hence the genotype of child will be IB IO.

Detailed explanation-2: -Similarly, someone who is blood type B could have a genotype of either BB or BO. A blood test of either type AB or type O is more informative.

Detailed explanation-3: -If a man with type AB blood marries a woman with type O, the children will have blood types A and B. Each blood type will be a fraction of ½. This is because ‘A’ and ‘B’ alleles are dominant alleles on ‘O’. So O allele will not show its effect in heterozygous conditions.

Detailed explanation-4: -Answer and Explanation: The possible phenotypes of the offspring between a man with blood type B and a woman with blood type A are A, B, O, and AB. Based on the Punnett Square, and depending on the genotypes of the parents, the offspring would have different blood types.

There is 1 question to complete.