AP BIOLOGY

HEREDITY

MUTATIONS

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
TRANSLATE this RNA sequence:AUGCAAUGA
A
Met-Glu-Stop
B
Met-His-Stop
C
Thr-Glu-Stop
D
Thr-Pro-Stop
Explanation: 

Detailed explanation-1: -The presence of a stop codon-UAA, UAG or UGA-in the A site of the ribosome is generally a signal to terminate protein synthesis. This process constitutes the last essential stage of translation, as it ensures the formation of full-sized proteins.

Detailed explanation-2: -A stop codon is a sequence of three nucleotides (a trinucleotide) in DNA or messenger RNA (mRNA) that signals a halt to protein synthesis in the cell. There are 64 different trinucleotide codons: 61 specify amino acids and 3 are stop codons (i.e., UAA, UAG and UGA).

Detailed explanation-3: -After mRNA leaves the nucleus, it moves to a ribosome, which consists of rRNA and proteins. The ribosome reads the sequence of codons in mRNA. Molecules of tRNA bring amino acids to the ribosome in the correct sequence. Translation of the codons in mRNA to a chain of amino acids occurs at a ribosome.

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