AP BIOLOGY

HEREDITY

THE PEDIGREE

Question [CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
One dog carries homozygous, long-haired traits (SS), and its mate carries homozygous short-haired traits (ss). Use a Punnett square to determine the probability of one of their offspring having long hair.
A
100%
B
75%
C
50%
D
25%
Explanation: 

Detailed explanation-1: -Short hair is dominant which means it can express in both heterozygous(Hh) and homozygous condition(HH). If all the progeny have short hair, then the parents should have been either: HH x HH OR HH x Hh OR HH x hh.

Detailed explanation-2: -The gene carrying the long hair trait in cats is recessive. That means the result of a shorthaired cat mating with a longhaired will only be shorthaired kittens. However, if the shorthaired offspring were to mate with each other, a handful of longhaired kittens might be born.

Detailed explanation-3: -In guinea pigs, short hair (H) is dominant to long hair (h), and the heterozygous condition when you cross a yellow coat (CY) and white coat (CW) gives you a cream coat. These two loci are located on different chromosomes. A heterozygous short-haired cream guinea pig is crossed with a long-haired white guinea pig.

Detailed explanation-4: -Since the parents are both heterozygous for hair length, their offspring is expected to be 50% heterozygous for hair length.

There is 1 question to complete.