LABORATORY REVIEW
CELL RESPIRATION
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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2 ATP and lactic acid.
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36 ATP and lactic acid.
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2 ATP and ethanol.
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36 ATP and ethanol.
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Detailed explanation-1: -Answer: In animal tissue (like muscles) the end product of anaerobic respiration is lactic acid. Here one molecule of glucose is broken down to produce two molecules of lactic acid. 2 ATPs are produced in the process.
Detailed explanation-2: -Lactic acid fermentation has two steps: glycolysis and NADH regeneration. During glycolysis, one glucose molecule is converted to two pyruvate molecules, producing two net ATP and two NADH.
Detailed explanation-3: -Lactic acid is an end product of anaerobic respiration in animals.
Detailed explanation-4: -In anaerobic conditions, pyruvate converts to lactate through anaerobic glycolysis. Anaerobic respiration results in the production of 2 ATP molecules.[5] Glucose is a hexose sugar, meaning it is a monosaccharide with six carbon atoms and six oxygen atoms.
Detailed explanation-5: -Lactic acid is the byproduct of anaerobic respiration in animals. Without molecule oxygen, anaerobic respiration occurs in animal muscle cells. As a result, it is often referred to as homolactic fermentation. The liver receives the lactic acid that muscle cells produce to regenerate glucose.