LABORATORY REVIEW
ENZYME CATALYSIS
Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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The change in free energy of the reaction is positive.
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The activation energy of the reaction is high.
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The change in free energy of the reaction is negative.
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This is a condensation reaction.
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The free energy of the products is higher than the free energy of the reactants.
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Detailed explanation-1: -For the given case of sucrose hydrolysis, the activation energy is high. Hence, sucrose will not be able to be converted into glucose and fructose as the reaction of sucrose breakdown has high activation energy.
Detailed explanation-2: -The hydrolysis of sucrose to glucose and fructose is exergonic. However, if you dissolve sucrose in water and keep the solution overnight at room temperature, there is no detectable conversion to glucose and fructose. This is because b. The activation energy of the reaction is high.
Detailed explanation-3: -On hydrolysis, the enthalpy decreases by 14.4 kJ/mol of sucrose at 310 K, and the heat capacity, Cp, increases by 61 J mol-1 K-1 of sucrose in the solution. The enthalpy of hydrolysis decreases with increase in the temperature and DeltaCp on hydrolysis increases.
Detailed explanation-4: -Hydrolysis of sucrose gives:-Sucrose + H2O =Glucose + Fructose. Equilibrium constant K for the reaction is 2 x 10 to the power 13 at 300 K.
Detailed explanation-5: -Answer and Explanation: Sucrose undergoing hydrolysis to form glucose and fructose is exergonic.