LABORATORY REVIEW
MOLECULAR BIOLOGY
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Question
[CLICK ON ANY CHOICE TO KNOW THE RIGHT ANSWER]
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TTT-CAG-CTG
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AAA-CAG-CTG
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AAA-GUC-GAC
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UUU-GUC-GAC
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Detailed explanation-1: -The template strand of DNA has AAA sequence, which will be transcribed to mRNA as UUU.
Detailed explanation-2: -The translation between mRNA and amino acids is the same for all living things. (For example, the mRNA codon CAG codes for glutamine in all living things.)
Detailed explanation-3: -The genetic code includes 64 possible permutations, or combinations, of three-letter nucleotide sequences that can be made from the four nucleotides. Of the 64 codons, 61 represent amino acids, and three are stop signals. For example, the codon CAG represents the amino acid glutamine, and TAA is a stop codon.
Detailed explanation-4: -This leads to a total of 10 codons in the mRNA sequence AUGGCAGUGCCA as AUG, UGG, GGC, GCA, CAG, AGU, GUG, UGC, GCC, CCA.